2=-2x^2+16x-33

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Solution for 2=-2x^2+16x-33 equation: 



2=-2x^2+16x-33

We move all terms to the left:

2-(-2x^2+16x-33)=0

We get rid of parentheses

2x^2-16x+33+2=0

We add all the numbers together, and all the variables

2x^2-16x+35=0

a = 2; b = -16; c = +35;
Δ = b2-4ac
Δ = -162-4·2·35
Δ = -24
Delta is less than zero, so there is no solution for the equation

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